ddd hh -> ddd+hh/24 yyyy mm -> yyyy+mm/12 yyyy ddd -> yyyy+ddd/365 yyyy ddd hh -> yyyy+ddd/365+hh/365/24 yyyy mm dd hh -> yyyy+(ddd+hh/24)/365, ddd=dd+D0[$m]Perhaps confusingly, the dates pictures are recognised by their *length*, so that if you ask for mmddhh (which has length 6) it will interpret this as yyyymm. Sorry about this - its just life.
Is that clear?